Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 12 - Section 12.5 - Equations of Lines and Planes - 12.5 Exercises - Page 833: 74

Answer

$\frac{\sqrt {14}}{42}$

Work Step by Step

Distance formula between two parallel planes is given as: $D=\frac{|ax+by+cz+d|}{\sqrt {a^2+b^2+c^2}}$ $D=\frac{|1-0+0-0|}{\sqrt {3^2+6^2+9^2}}=\frac{1}{\sqrt {126}}$ $=\frac{\sqrt {14}}{42}$
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