Answer
$\frac{18}{7}$
Work Step by Step
Given: $(1,-2,4)$ ; $3x+2y+6z=5$
Distance formula between the point and the plane is given as:
$D=\frac{|ax+by+cz+d|}{\sqrt {a^2+b^2+c^2}}$
$D=\frac{|3.1+2 \cdot (-2)+6 \cdot (4)-5|}{\sqrt {3^2+2^2+6^2}}$
$=\frac{18}{7}$
