Answer
$\frac{5}{2\sqrt {14}}$
Work Step by Step
Distance formula between two parallel planes is given as:
$D=\frac{|ax+by+cz+d|}{\sqrt {a^2+b^2+c^2}}$
$D=\frac{|0+0+2 \times 4-3|}{\sqrt {4^2+6^2+2^2}}=\frac{5}{\sqrt {56}}$
$=\frac{5\sqrt {14}}{28}$
$=\frac{5}{2\sqrt {14}}$
