Answer
$x=1+1.6t,y=2.4-1.2t,z=4.6-4.3t$
and
$\frac{x-1}{1.6}=\frac{y-2.4}{-1.2}=\frac{z-4.6}{-4.3}$
Work Step by Step
The direction vector for a line through the $(1,2.4,4.6)$ and the point $(2.6,1.2,0.3)$ is $\lt 1.6,-1.2,-4.3 \gt$ .
Parametric equations defined by:
$x=x_0+at$, $y=y_0=bt$ and $z=z_0+ct$
Thus, the parametric equations are:
$x=1+1.6t,y=2.4-1.2t,z=4.6-4.3t$
The symmetric equations are defined by:
$\frac{x-x_0}{a}=\frac{y-y_0}{b}=\frac{z-z_0}{c}$
Hence, the symmetric equations are:
$\frac{x-1}{1.6}=\frac{y-2.4}{-1.2}=\frac{z-4.6}{-4.3}$
