Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 12 - Section 12.5 - Equations of Lines and Planes - 12.5 Exercises - Page 831: 2

Answer

$r=\lt 6+t,-5+3t,2-\frac{2}{3}t\gt $ and $x=6+t,y=-5+3t,z=2-\frac{2}{3}t $

Work Step by Step

Equation of the line is given by $r=r_0+tv$ $r=\lt 6,-5,2\gt $ and $v=\lt 1,3,\frac{-2}{3}\gt $, so the equation is $r=\lt 6,-5,2\gt +\lt t,3t,\frac{-2}{3}t\gt $ In order to get the parametric equations, we will take the sum. $r=\lt 6+t,-5+3t,2-\frac{2}{3}t\gt $ and $x=6+t,y=-5+3t,z=2-\frac{2}{3}t $
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