Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 12 - Section 12.4 - The Cross Product - 12.4 Exercises - Page 821: 15

Answer

$96\sqrt 3$, into the page

Work Step by Step

If we take vector u and move it in such a way that it's direction stays the same and it's starting point is the same as the starting point of vector v, the acute angle between vectors u and v is 60 degrees ($180-120=60$). 60 degrees is $\frac{2\pi}{3}$ so θ= $\frac{2\pi}{3}$ |u x v| = $|u||v| sin(θ)$= $12⋅16⋅sin(\frac{2π}{3})$=$96\sqrt 3$ To close the acute angle between u and v following the right hand rule, the thumb points inwards, so: into the paper.
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