## Calculus: Early Transcendentals 8th Edition

$96\sqrt 3$, into the page
If we take vector u and move it in such a way that it's direction stays the same and it's starting point is the same as the starting point of vector v, the acute angle between vectors u and v is 60 degrees ($180-120=60$). 60 degrees is $\frac{2\pi}{3}$ so θ= $\frac{2\pi}{3}$ |u x v| = $|u||v| sin(θ)$= $12⋅16⋅sin(\frac{2π}{3})$=$96\sqrt 3$ To close the acute angle between u and v following the right hand rule, the thumb points inwards, so: into the paper.