Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 12 - Section 12.4 - The Cross Product - 12.4 Exercises - Page 821: 11

Answer

$(j-k ) \times (k-i)=i+j+k$

Work Step by Step

Cross product of a vector with itself is zero. We are given $(j-k ) \times (k-i)$ $(j-k ) \times (k-i)=j \times (k-i)-k \times (k-i)$ $=j \times k-j \times i-k\times k+k \times i$ $=i-(-k)-0+j$ $=i+j+k$ Hence,$(j-k ) \times (k-i)=i+j+k$
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