Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 12 - Section 12.2 - Vectors - 12.2 Exercises - Page 806: 43

Answer

$\vec{AB}$ $+$ $\vec{BC}$ $+$ $\vec{CA}$ $=$ $\bf{0}$

Work Step by Step

By the Triangle Law, $\vec{AB}$ $+$ $\vec{BC}$ $=$ $\vec{AC}$ Then $\vec{AB}$ $+$ $\vec{BC}$ $+$ $\vec{CA}$ $=$ $\vec{AC}$ $+$ $\vec{CA}$ but $\vec{AC}$ $+$ $\vec{CA}$ $=$ $\vec{AC}$ $+$$($ $-$ $\vec{AC}$$)$ $=$ $\bf{0}$ So $\vec{AB}$ $+$ $\vec{BC}$ $+$ $\vec{CA}$ $=$ $\bf{0}$
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