Answer
$F_T=1285N$
$N60^oW$
Work Step by Step
$500lb=227kg$
$F_G=227kg\times9.81m/s^2=-2227N$
$F_{Ty}=\frac{2227N}{2}=1113N$
$F_{Tx}=F_{Ty}\times\tan(30^o)=1113N\times\tan(30^o)=642.6N$
$F_T=\sqrt{(1113N)^2+(642.6N)^2}=1285N$
$N60^oW$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 12 - Section 12.2 - Vectors - 12.2 Exercises - Page 806: 36
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