## Calculus: Early Transcendentals 8th Edition

$\boldsymbol{F}=\langle39.4,30.785\rangle$.
Imagine a force vector $\boldsymbol{F}=\langle x,y\rangle$. We know $|\boldsymbol{F}|=50N$ and $\theta=38^\circ$ from the x axis. In order to find the components of $\boldsymbol{F}$ we apply trigonometry: $x=50\cos{38^\circ}=50\times0.788=39.4$ $y=50\sin{38^\circ}=50\times0.6157=30.785$