Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 12 - Section 12.2 - Vectors - 12.2 Exercises - Page 805: 28

Answer

The angle between the vector $\langle8,6\rangle$ and the x axis is $\theta=36.87^\circ$.

Work Step by Step

In order to find the angle between the vector $\langle8,6\rangle$ and the x axis we can simply imagine a triangle with a base of $8$ and a height of $6$. As a result we can find $\theta$ with simple trigonometry. $\tan{\theta}=\frac{6}{8}=\frac{3}{4}\Rightarrow\theta=\arctan{\frac{3}{4}}\approx36.87^\circ$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.