Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 11 - Section 11.9 - Representations of Functions as Power Series - 11.9 Exercises - Page 757: 19

Answer

$\sum_{n=0}^{\infty}(2n+1)x^{n}$, $R=1$

Work Step by Step

$f(x)=\frac{1+x}{(1-x)^{2}}=\sum_{n=0}^{\infty}(2n+1)x^{n}$ $\lim\limits_{n \to \infty}|\frac{a_{n+1}}{a_{n}}|=\lim\limits_{n \to \infty}|\frac{(2(n+1)+1)x^{n+1}}{(2n+1)x^{n}}|$ $=|x|\lt 1$ The given series converges with $R=1$
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