Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 11 - Section 11.9 - Representations of Functions as Power Series - 11.9 Exercises - Page 757: 18

Answer

$\sum_{n=2}^{\infty}n(n-1)\frac{x^{n+1}}{2^{n+2}}$, $R=2$

Work Step by Step

$f(x)=(\frac{x}{2-x})^{3}=\sum_{n=2}^{\infty}n(n-1)\frac{x^{n+1}}{2^{n+2}}$ $\lim\limits_{n \to \infty}|\frac{a_{n+1}}{a_{n}}|=\lim\limits_{n \to \infty}|\frac{(n+1)((n+1)-1)\frac{x^{n+2}}{2^{n+3}}}{n(n-1)\frac{x^{n+1}}{2^{n+2}}}|$ $=|\frac{x}{2}|\lt 1$ The given series converges with $R=2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.