Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

APPENDIX D - Trigonometry - D Exercises - Page A 33: 77

Answer

$\angle C=62^\circ$ a=199.55 b=241.52

Work Step by Step

$\angle C=180^\circ-50^\circ-68^\circ=62^\circ$ According the Law of Sines $\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}$, thus: $\frac{\sin 50^\circ}{a}=\frac{\sin 68^\circ}{b}=\frac{\sin 62^\circ}{230}$ a=199.55 b=241.52
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