Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

APPENDIX D - Trigonometry - D Exercises - Page A 33: 76



Work Step by Step

$sinx>cosx$ Let us simplify the above equation. $sinx=cosx$ Thus, $tanx=1$ This is true for x = $\frac{\pi}{4},\frac{5 \pi}{4}$ Hence, the solutions for the given equation is $\pi/4
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.