# APPENDIX D - Trigonometry - D Exercises: 67

$\frac{\pi}{4},\frac{3\pi}{4},\frac{5 \pi}{4}\frac{7 \pi}{4}$

#### Work Step by Step

We need to find the range for $x$ for the equation $2sin^{2}x=1$ $sin^{2}x=\frac{1}{2}$ or $sinx=±\frac{1}{\sqrt 2} =±\frac{\sqrt 2}{ 2}$ This is true for x=$\frac{\pi}{4},\frac{3\pi}{4},\frac{5 \pi}{4}\frac{7 \pi}{4}$

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