Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

APPENDIX D - Trigonometry - D Exercises - Page A 33: 67

Answer

$\frac{\pi}{4},\frac{3\pi}{4},\frac{5 \pi}{4}\frac{7 \pi}{4}$

Work Step by Step

We need to find the range for $x$ for the equation $2sin^{2}x=1$ $sin^{2}x=\frac{1}{2}$ or $sinx=±\frac{1}{\sqrt 2} =±\frac{\sqrt 2}{ 2}$ This is true for x=$\frac{\pi}{4},\frac{3\pi}{4},\frac{5 \pi}{4}\frac{7 \pi}{4}$
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