Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 9 - Power Series - 9.1 Approximating Functions with Polynomials - 9.1 Exercises - Page 672: 3

Answer

1; 1.05; 1.04875

Work Step by Step

We are given: $f(x)=\sqrt{1+x}$ and the first three Taylor polynomials for $f(x)$ centered at 0: $p_0(x)=1$ $p_1(x)=1+\dfrac{x}{2}$ $p_2(x(=1+\dfrac{x}{2}-\dfrac{x^2}{8}$ Consider $x=0.1$. Determine the first approximation using $p_0(x)$: $p_0(0.1)=1$ Determine the second approximation using $p_1(x)$: $p_1(0.1)=1+\dfrac{0.1}{2}=1+0.05=1.05$ Determine the third approximation using $p_2(x)$: $p_2(0.1)=1+\dfrac{0.1}{2}-\dfrac{0.1^2}{8}=1+0.05-0.00125=1.04875$
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