Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 9 - Power Series - 9.1 Approximating Functions with Polynomials - 9.1 Exercises - Page 672: 23

Answer

a) 1.0246875; b) Absolute error: $7.6\cdot 10^{-6}$

Work Step by Step

We are given the function $f$ and the Taylor polynomial $p_2$: $f(x)=\sqrt{1+x}$ $p_2(x)=1+\dfrac{x}{2}-\dfrac{x^2}{8}$ a) Let $x=0.05$ Compute $p_2(x)$ for $x=0.05$: $p_2(0.05)=1+\dfrac{0.05}{2}-\dfrac{0.05^2}{8}=1.0246875$ b) Use a computer to determine the exact value of $\sqrt{1.05}$: $\sqrt{1.05}=1.0246951 Determine the absolute error: $|\text{exact value}-\text{approximating value}|=|1.0246951-1.0246875|=0.0000076=7.6\cdot 10^{-6}$
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