Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 8 - Sequences and Infinite Series - 8.6 Alternating Series - 8.6 Exercises - Page 657: 33

Answer

$$n=10$$

Work Step by Step

Recall the formula that $\text{Error}=|R_n| \leq a_{n+1}$ Here, we have $R_n \leq \dfrac{1}{(n+1)^4} \lt 10^{-4}$ and $ (n+1)^4 \gt 10^{4}$ or, $(n+1)^4 \gt 10^4$ or, $n \gt 10-1$ or, $n \gt 9$ or, $n=10$
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