Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 8 - Sequences and Infinite Series - 8.6 Alternating Series - 8.6 Exercises - Page 657: 29

Answer

$n=10^4$

Work Step by Step

Recall the formula that $\text{Error}=|R_n| \leq a_{n+1}$ Here, we have $R \leq \dfrac{1}{n+1}$ and $ \dfrac{1}{n+1} \lt 10^{-4}$ or, $n+1 \gt 10^4$ or, $n \gt 10^4 -1$ or, $n=10^4$
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