Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 4 - Applications of the Derivative - 4.1 Maxima and Minima - 4.1 Exercises - Page 243: 59

Answer

(a). $f(x) = sec (x) tan (x)$ which is zero when $tan (x) = 0$ (since $sec (x)$ is never zero.) So we are looking for where $\frac{sin (x)}{cos (x)} = 0$, which is when $sin (x) = 0$, which is at $x = 0$. b. $f(−π/4) =√2 = f(π/4)$ and $f(0) = 1$. So the absolute maximum for $f$ is $√2$ and the absolute minimum is 1.

Work Step by Step

See the graph for explanation.
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