## Calculus: Early Transcendentals (2nd Edition)

Published by Pearson

# Chapter 4 - Applications of the Derivative - 4.1 Maxima and Minima - 4.1 Exercises - Page 243: 39

#### Answer

(a). $f(x) = −2 cos x sin x$, which is zero for $x = 0$, $x = π/2$, and $x = π$. Since there are endpoints at $x = 0$ and $x = π$, only $(π/2, 1)$ is a critical point. (b). We have that $f(0) = 1$, $f(π/2) = 0$, and $f(π) = 1$, so the maximum value of $f$ on this interval is $1$ and the minimum is $0$.

#### Work Step by Step

See the graph for explanation.

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