Answer
(a). $f'(x) = 2x$, which is zero for $x = 0$.
(b). We have that $f(−2) = −6$, $f(0) = −10$, and
$f(3) = −1$, so the maximum value of $f$ on this
interval is $−1$ and the minimum is $−10$.
Work Step by Step
See the graph for explanation.
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 4 - Applications of the Derivative - 4.1 Maxima and Minima - 4.1 Exercises - Page 243: 37
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