Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - Review Exercises - Page 233: 30


$\frac{d}{dx}\log_3(x+8) = \frac{1}{(x+8)ln(3)}$

Work Step by Step

$\frac{d}{dx}\log_b(x) = \frac{1}{x\ln(b)}$ $\frac{d}{dx}\log_3(x+8) = \frac{1}{(x+8)\ln(3)}$
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