Answer
$\frac{d}{d\theta}(\tan(\sin(\theta)) = \sec^2(\sin(\theta))\cos(\theta)$
Work Step by Step
Using Chain Rule:
$\frac{d}{d\theta}(\tan(\sin(\theta)) = \sec^2(\sin(\theta)) \times \frac{d}{d\theta}\sin(\theta) = \sec^2(\sin(\theta))\cos(\theta)$
