Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - Review Exercises: 23

Answer

$\frac{d}{d\theta}(\tan(\sin(\theta)) = \sec^2(\sin(\theta))\cos(\theta)$

Work Step by Step

Using Chain Rule: $\frac{d}{d\theta}(\tan(\sin(\theta)) = \sec^2(\sin(\theta)) \times \frac{d}{d\theta}\sin(\theta) = \sec^2(\sin(\theta))\cos(\theta)$
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