Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - Review Exercises - Page 233: 23


$\frac{d}{d\theta}(\tan(\sin(\theta)) = \sec^2(\sin(\theta))\cos(\theta)$

Work Step by Step

Using Chain Rule: $\frac{d}{d\theta}(\tan(\sin(\theta)) = \sec^2(\sin(\theta)) \times \frac{d}{d\theta}\sin(\theta) = \sec^2(\sin(\theta))\cos(\theta)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.