Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - Review Exercises: 17

Answer

$10t\sin t+5t^{2}\cos t$

Work Step by Step

$\dfrac {d}{dt}\left( 5t^{2}\sin t\right) =\left( \dfrac {d}{dt}\left( 5t^{2}\right) \right) \times \sin t+\left( \dfrac {d}{dt}\left( \sin t\right) \right) \times 5t^{2}=10t\sin t+5t^{2}\cos t$
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