Answer
$10t\sin t+5t^{2}\cos t$
Work Step by Step
$\dfrac {d}{dt}\left( 5t^{2}\sin t\right) =\left( \dfrac {d}{dt}\left( 5t^{2}\right) \right) \times \sin t+\left( \dfrac {d}{dt}\left( \sin t\right) \right) \times 5t^{2}=10t\sin t+5t^{2}\cos t$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 3 - Derivatives - Review Exercises - Page 233: 17
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