Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - Review Exercises: 9


$\lim\limits_{x \to 1}{\sqrt {5x+6}}=\sqrt {11}$

Work Step by Step

$\lim\limits_{x \to 1}{\sqrt {5x+6}}=\sqrt {\lim\limits_{x \to 1}{(5x+6)}}=\sqrt {\lim\limits_{x \to 1}{5x}+6}=\sqrt {5\times\lim\limits_{x \to 1}{x}+6}=\sqrt {5\times1+6}=\sqrt {11}$
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