Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - Review Exercises - Page 124: 25

Answer

$-\infty $

Work Step by Step

$\lim _{x\rightarrow 5}\dfrac {x-7}{x\left( x-5\right) ^{2}}=\dfrac {5-7}{5\times \left( 5-5\right) ^{2}}=\dfrac {-2}{5\times 0^{2}}=-\infty $
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