Answer
$-\infty $
Work Step by Step
$\lim _{x\rightarrow 5}\dfrac {x-7}{x\left( x-5\right) ^{2}}=\dfrac {5-7}{5\times \left( 5-5\right) ^{2}}=\dfrac {-2}{5\times 0^{2}}=-\infty $
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