Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.6 Continuity - 2.6 Exercises - Page 110: 77

Answer

$$0$$

Work Step by Step

$$\eqalign{ & {\text{Calculate }}\mathop {\lim }\limits_{x \to \infty } \frac{{{{\tan }^{ - 1}}x}}{x} \cr & {\text{Evaluate the limit}} \cr & {\text{ }} = \mathop {\lim }\limits_{x \to \infty } \frac{{\overbrace {\left( {{{\tan }^{ - 1}}x} \right)}^{{\text{approaches to }}\frac{\pi }{2}}}}{{\underbrace {x}_{{\text{approaches to }}\infty }}} \cr & {\text{ }} = \frac{{\frac{\pi }{2}}}{\infty } = 0 \cr & {\text{Therefore}}{\text{,}} \cr & \mathop {\lim }\limits_{x \to \infty } \frac{{{{\tan }^{ - 1}}x}}{x} = 0 \cr} $$
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