Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.6 Continuity - 2.6 Exercises - Page 110: 78

Answer

$0$

Work Step by Step

$-\dfrac {1}{e^{3t}}\leq \dfrac {\cos t}{e^{3t}}\leq \dfrac {1}{e^{3t}}$ $\Rightarrow \lim _{t\rightarrow \infty }-\dfrac {1}{e^{3t}}=\dfrac {1}{e^{3t}}=0\Rightarrow \lim _{t\rightarrow \infty }\dfrac {\cos t}{e^{3t}}=0$
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