Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.6 Continuity - 2.6 Exercises: 71

Answer

$1$

Work Step by Step

$\lim _{x\rightarrow \pi }\dfrac {\cos ^{2}x+3\cos x+2}{\cos x+1}=\dfrac {\left( \cos x+1\right) \left( \cos x+2\right) }{\cos x+1}=\cos x+2=\cos \pi +2=-1+2=1$
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