Answer
$-\infty$
Work Step by Step
$\lim _{x\rightarrow -\infty }\left( 2x-8+4x^{3}\right) =\dfrac {2}{x^{8}}+4x^{3}=0+4x^{3}=4\times \left( -\infty \right) =-\infty $
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 2 - Limits - 2.5 Limits at Infinity - 2.5 Exercises - Page 96: 24
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