Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.5 Limits at Infinity - 2.5 Exercises: 21

Answer

$-\infty$

Work Step by Step

$$\lim _{x\rightarrow -\infty }\left( -3x^{16}+2\right) =x^{16}\left( -3+\dfrac {2}{x^{16}}\right) =x^{16}\left( -3+0\right) =-3x^{16}=-\infty $$
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