Chapter 2 - Limits - 2.5 Limits at Infinity - 2.5 Exercises - Page 96: 11

$0$

$\dfrac {-1}{\theta^2 }\leq \dfrac {\cos \theta }{\theta ^2}\leq \dfrac {1}{\theta^2 }$ $\lim _{\theta \rightarrow \infty }\dfrac {-1}{\theta ^2}=0$ $\lim _{\theta \rightarrow \infty }\dfrac {1}{\theta ^2}=0$ $0\leq \dfrac {\cos \theta }{\theta ^{2}}\leq 0\Rightarrow \lim _{\theta \rightarrow \infty }\dfrac {\cos \theta }{\theta ^{2}}=0$