Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 12 - Functions of Several Veriables - 12.5 The Chain Rule - 12.5 Exercises - Page 913: 6

Answer

$$\frac{dy}{dx} =- \frac{\partial F}{\partial x}/\frac{\partial F}{\partial y}.$$

Work Step by Step

By differentiation with respect to $x$, we have $$ \frac{\partial F}{\partial x} + \frac{\partial F}{\partial y} \frac{dy}{dx} =0. $$That is $$\frac{dy}{dx} =- \frac{\partial F}{\partial x}/\frac{\partial F}{\partial y}.$$
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