Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 11 - Vectors and Vector-Valued Functions - 11.6 Calculus of Vector-Valued Functions - 11.6 Exercises: 4

Answer

$\textbf{r}''(t) = \langle 90t^8, 0, -cos(t) \rangle$

Work Step by Step

$\textbf{r}(t) = \langle t^{10}, 8t, cos(t) \rangle$ $\textbf{r}'(t) = \langle 10t^9, 8, -sin(t) \rangle$ $\textbf{r}''(t) = \langle 90t^8, 0, -cos(t) \rangle$
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