Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 11 - Vectors and Vector-Valued Functions - 11.1 Vectors in the Plane - 11.1 Exercises - Page 768: 47

Answer

$\left(-\dfrac{28\sqrt{74}}{74},\dfrac{20\sqrt{74}}{74}\right)$ $\left(\dfrac{28\sqrt{74}}{74},-\dfrac{20\sqrt{74}}{74}\right)$

Work Step by Step

We are given the points: $P(-4,1)$ $Q(3,-4)$ $R(2,6)$ Find the unit vector $\overrightarrow{u}$ with the same direction as $\overrightarrow{QP}$: $\overrightarrow{u}=\dfrac{\overrightarrow{QP}}{|\overrightarrow{QP}|}=\dfrac{(-4-3,1-(-4))}{\sqrt{(-4-3)^2+[1-(-4)]^2}}=\dfrac{(-7,5)}{\sqrt{74}}=\left(-\dfrac{7}{\sqrt{74}},\dfrac{5}{\sqrt{74}}\right)=\left(-\dfrac{7\sqrt{74}}{74},\dfrac{5\sqrt{74}}{74}\right)$ Two vectors parallel to $\overrightarrow{QP}$ of length 4 are: $4\overrightarrow{u}=4\left(-\dfrac{7\sqrt{74}}{74},\dfrac{5\sqrt{74}}{74}\right)=\left(-\dfrac{28\sqrt{74}}{74},\dfrac{20\sqrt{74}}{74}\right)$ $-4\overrightarrow{u}=-4\left(-\dfrac{7\sqrt{74}}{74},\dfrac{5\sqrt{74}}{74}\right)=\left(\dfrac{28\sqrt{74}}{74},-\dfrac{20\sqrt{74}}{74}\right)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.