Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 11 - Vectors and Vector-Valued Functions - 11.1 Vectors in the Plane - 11.1 Exercises - Page 768: 37

Answer

$\sqrt{194}$

Work Step by Step

We are given: $u=(3,-4)$ $v=(1,1)$ $w=(-1,0)$ Determine $|2u+3v-4w|$: $|2u+3v-4w|=|2(3,-4)+3(1,1)-4(-1,0)|=|(6,8)+(3,3)+(4,0)|=|(6+3+4,-8+3+0|=|(13,-5)|=\sqrt{13^2+(-5)^2}=\sqrt{194}$
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