Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 11 - Vectors and Vector-Valued Functions - 11.1 Vectors in the Plane - 11.1 Exercises - Page 768: 36

Answer

$3\sqrt 2$

Work Step by Step

We are given: $u=(3,-4)$ $v=(1,1)$ $w=(-1,0)$ Determine $|u+v+w|$: $|u+v+w|=|(3,-4)+(1,1)+(-1,0)|=|(3+1+(-1),-4+1+0|=|(3,-3)|=\sqrt{3^2+(-3)^2}=\sqrt{18}=3\sqrt 2$
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