Answer
$$\eqalign{
& y = 3 \cr
& {\text{The graph or the curve is the horizontal line }}y = 3 \cr} $$
Work Step by Step
$$\eqalign{
& r = 3\csc \theta \cr
& {\text{Use the reciprocal identity csc}}\theta = \frac{1}{{\sin \theta }} \cr
& r = 3\left( {\frac{1}{{\sin \theta }}} \right) \cr
& r\sin \theta = 3 \cr
& {\text{Where }}r\sin \theta = y.{\text{ So}}{\text{,}} \cr
& y = 3 \cr
& {\text{The graph or the curve is the horizontal line }}y = 3 \cr} $$