Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 10 - Parametric and Polar Curves - 10.2 Polar Coordinates - 10.2 Exercises - Page 729: 15

Answer

$$\left( {\frac{{3\sqrt 2 }}{2},\frac{{3\sqrt 2 }}{2}} \right)$$

Work Step by Step

$$\eqalign{ & \left( {3,\frac{\pi }{4}} \right) \Rightarrow r = 3{\text{ and }}\theta = \frac{\pi }{4} \cr & {\text{Converting to cartesian coordinates }}\left( {x,y} \right).{\text{ Where}} \cr & x = r\cos \theta {\text{ and }}y = r\sin \theta \cr & {\text{We obtain}}{\text{,}} \cr & x = 3\cos \left( {\frac{\pi }{4}} \right) = 3\left( {\frac{{\sqrt 2 }}{2}} \right) = \frac{{3\sqrt 2 }}{2} \cr & y = r\sin \left( {\frac{\pi }{4}} \right) = 3\left( {\frac{{\sqrt 2 }}{2}} \right) = \frac{{3\sqrt 2 }}{2} \cr & {\text{The cartesian coordinates are:}} \cr & \left( {x,y} \right) = \left( {\frac{{3\sqrt 2 }}{2},\frac{{3\sqrt 2 }}{2}} \right) \cr} $$
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