Answer
$\boxed{\theta= \frac{\pi}{6}, \frac{5\pi}{6}, \frac{7\pi}{6}, \frac{11\pi}{6}}$
Work Step by Step
$sin^2(\theta) = \frac{1}{4}$ which means $sin(\theta) = +\frac{1}{2}$ or $sin(\theta) = -\frac{1}{2}$.
For the first case, $sin(\theta) = +\frac{1}{2}$, $\theta = \frac{\pi}{6}, \frac{5\pi}{6}$.
For the second case, $sin(\theta) = -\frac{1}{2}$, $\theta = \frac{7\pi}{6}, \frac{11\pi}{6}$.
Overall, the solutions for $\theta$ are: $\frac{\pi}{6}, \frac{5\pi}{6}, \frac{7\pi}{6}, \frac{11\pi}{6}$
