Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.4 Trigonometric Functions and Their Inverse - 1.4 Exercises - Page 48: 17

Answer

$\boxed{1}$

Work Step by Step

$\tan(-3\pi/4) = \dfrac{\sec(-3\pi/4)}{\csc(-3\pi/4)}= \dfrac{-\frac{\sqrt{2}}{2}}{-\frac{\sqrt{2}}{2}} = 1$. This can be easily verified by a calculator.
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