Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.4 Trigonometric Functions and Their Inverse - 1.4 Exercises - Page 48: 10

Answer

The function $\cos x$ must be restricted in order to have an inverse.

Work Step by Step

The function $f(x)=\cos x$ is not an one-to-one function over its whole domain, therefore in order for the function to have an inverse we must restrict the domain so that the function is one-to-one. For example the domain of $f$ might be $[0,\pi]$. The restriction of $f(x)$ has the domain and range: $D_f=[0,\pi]$ $R_f=[0,1]$ The inverse $f^{-1}(x)=\cos^{-1} x$ has the domain and range: $D_{f^{-1}}=[0,1]$ $R_{f^{-1}}=[0,\pi]$ Therefore $\cos^{-1} x\in [0,\pi]$.
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