Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.1 Review of Functions - 1.1 Exercises - Page 12: 99


The function is even.

Work Step by Step

We have that $E(-x)=E(x)$ and $O(-x)=-O(x)$. Let $\Phi=E\circ E$. Then $$\Phi(-x)=E\circ E(-x)=E(E(-x))=E(E(x))=E\circ E(x)=\Phi(x)$$ which means that the function is even.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.