#### Answer

The solution is
$$f(x)=3x-2.$$

#### Work Step by Step

The right side is a polynomial of the $1st$ degree so we will ask that $f(x)$ be a polynomial of the first degree i.e. it will be of the form of $f(x)=ax+b$. Then we have
$$f(f(x))=f(ax+b)=a(ax+b)+b=a^2x+ab+b=9x-8.$$
This means that $a^2=9\rightarrow a=3$ and $ab+b=-8\Rightarrow3b+b=-8\Rightarrow4b=-8\Rightarrow b=-2.$
So finally $f(x)=3x-2.$