#### Answer

The function is even.

#### Work Step by Step

We have that $E(-x)=E(x)$ and $O(-x)=-O(x)$.
Let $\Phi=O\circ E$. Then
$$\Phi(-x)=O\circ E(-x)=O(E(-x))=O(E(x))=O\circ E(x)=\Phi(x)$$
which means that the function is even.

Published by
Pearson

ISBN 10:
0321947347

ISBN 13:
978-0-32194-734-5

The function is even.

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