Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.1 Review of Functions - 1.1 Exercises: 101

Answer

The function is even.

Work Step by Step

We have that $E(-x)=E(x)$ and $O(-x)=-O(x)$. Let $\Phi=O\circ E$. Then $$\Phi(-x)=O\circ E(-x)=O(E(-x))=O(E(x))=O\circ E(x)=\Phi(x)$$ which means that the function is even.
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