Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.7 Hyperbolic Functions - 6.7 Exercises - Page 489: 6

Answer

a) $\sinh(1)\approx 1.1752$ b) $\sinh^{-1}(1)\approx 0.8814$

Work Step by Step

a) We know that: $$\sinh(x)=\frac{e^{x}-e^{-x}}{2}$$ Substitute $x=1$ into the equation: $$\sinh(1)=\frac{e^{1}-e^{-1}}{2}\approx 1.1752$$ -------------------------------------------------------- b) We know that: $$\sinh^{-1}(x)=\ln(x+\sqrt{x^{2}+1})$$ Substitute $x=1$ into the equation: $$\sinh^{-1}(1)=\ln(1+\sqrt{1^{2}+1})\approx 0.8814$$
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