Answer
$2\cot x$
Work Step by Step
$\frac{d}{dx}\ln(\sin^2 x)$
$=\frac{1}{\sin^2 x}*\frac{d}{dx}\sin^2 x$
$=\frac{1}{\sin^2 x}*2\sin x\frac{d}{dx}\sin x$
$=\frac{1}{\sin^2 x}*2\sin x\cos x$
$=\frac{2\cos x}{\sin x}$
$=2\cot x$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.