Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.4 Derivatives of Logarithmic Functions - 6.4 Exercises: 16

Answer

$\frac{1-3t^2}{1+t-t^3}$

Work Step by Step

$\frac{d}{dt}\ln|1+t-t^3|$ $=\frac{1}{1+t-t^3}*\frac{d}{dx}(1+t-t^3)$ $=\frac{1}{1+t-t^3}*(1-3t^2)$ $=\frac{1-3t^2}{1+t-t^3}$
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